tolong bantu jawab kak
16. Volume bangun 1 (tabung)
= π × r² × t
= 22/7 × 7 cm × 7 cm × 12 cm
= 1.848 cm³
Volume bangun 2 (kerucut)
= ⅓ × π × r² × t
= ⅓ × 22/7 × 7 cm × 7 cm × 6 cm
= 308 cm³
► Volume gabungan tersebut ◄
= 1.848 cm³ + 308 cm³
= 2.156 cm³
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17. Luas permukaan bangun 1 (balok atas)
= 2 × (pl + pt + lt)
= 2 × (12 cm × 5 cm + 12 cm × 5 cm + 5 cm × 5 cm)
= 2 × (60 cm² + 60 cm² + 25 cm²)
= 2 × 145 cm²
= 290 cm²
Luas permukaan bangun 2 (balok bawah)
= 2 × (pl + pt + lt)
= 2 × (18 cm × 5 cm + 18 cm × 6 cm + 5 cm × 6 cm)
= 2 × (90 cm² + 108 cm² + 30 cm²)
= 2 × 228 cm²
= 456 cm²
▻ Luas permukaan gabungan tersebut ◅
= 290 cm² + 456 cm²
= 746 cm²
━O━O━━━━━━━━━
・:。@justfebyy・:三
━━━━━━━━━━━━━
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